4[2t-(3-t)+s]=(-2+7t)

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Solution for 4[2t-(3-t)+s]=(-2+7t) equation:


Simplifying
4[2t + -1(3 + -1t) + s] = (-2 + 7t)
4[2t + (3 * -1 + -1t * -1) + s] = (-2 + 7t)
4[2t + (-3 + 1t) + s] = (-2 + 7t)

Reorder the terms:
4[-3 + s + 2t + 1t] = (-2 + 7t)

Combine like terms: 2t + 1t = 3t
4[-3 + s + 3t] = (-2 + 7t)
[-3 * 4 + s * 4 + 3t * 4] = (-2 + 7t)
[-12 + 4s + 12t] = (-2 + 7t)

Remove parenthesis around (-2 + 7t)
-12 + 4s + 12t = -2 + 7t

Solving
-12 + 4s + 12t = -2 + 7t

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 4s + 12 + 12t = -2 + 12 + 7t

Reorder the terms:
-12 + 12 + 4s + 12t = -2 + 12 + 7t

Combine like terms: -12 + 12 = 0
0 + 4s + 12t = -2 + 12 + 7t
4s + 12t = -2 + 12 + 7t

Combine like terms: -2 + 12 = 10
4s + 12t = 10 + 7t

Add '-12t' to each side of the equation.
4s + 12t + -12t = 10 + 7t + -12t

Combine like terms: 12t + -12t = 0
4s + 0 = 10 + 7t + -12t
4s = 10 + 7t + -12t

Combine like terms: 7t + -12t = -5t
4s = 10 + -5t

Divide each side by '4'.
s = 2.5 + -1.25t

Simplifying
s = 2.5 + -1.25t

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